Tuesday, February 27, 2007
Midpoint of a Line Segment
posted by siopao at 4:26 PM
At the beginning of today's class we did the POTD (problem of the day). I'm not going to give the solution because that is way too much work to do. But in case there is some on the blog that wants to try it, I'll put the problem.
.
Find a point on the x-axis that has a distance of 10units from the point (4,6)
.
We established that the midpoint of a line is the point directly in the middle of a line (the halfway mark)
.
The midpoint formula
This formula is basically finding the average of the Xs and the Ys.

The smaller numbers you see next to the Xs and Ys are subscripts
.
.
Find the midpoint of a line with pointA (5,6) and PointB (7,12)

.
.
Find the centre of a circle who's points of diameter are (3,-2) and (-2,4)
.
.
(9,11) is the midpoint of a line adjoined by (x,12) and (13,y) line x and y.



*sorry about the images, but when I try to enlarge them they do show up that great*
.
Ms. Armstrong assigned Exercise 5 for homework
.
And the next blogger will be JENNIFER
 



0 Comments:
« back home
Post a Comment




« back home
Post a Comment